22b^2-34b-20=0

Solution for 22b^2-34b-20=0 equation:

22b^2-34b-20=0

a = 22; b = -34; c = -20;
Δ = b2-4ac
Δ = -342-4·22·(-20)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-54}{2*22}=\frac{-20}{44}
=-5/11
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+54}{2*22}=\frac{88}{44}
=2
$